Multiply around a base

Keep signed differences from 100 or 1000, multiply the base part, then add or subtract the correction.

Give each difference its sign

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103 × 107a = +3 b = +7110 × 100= 1100011000 + 21= 11021
Positive differences give a positive correction.

Choose a nearby base B. Write the numbers as B + a and B + b. A difference above the base is positive; a difference below it is negative. Expanding the product gives (B + a)(B + b) = B(B + a + b) + ab.

For 103 × 107, use B = 100, a = +3 and b = +7. Add the differences to the base: 100 + 3 + 7 = 110. Multiply by the base: 110 × 100 = 11000. Add the correction 3 × 7 = 21 to get 11021.

Lesson help

Use B(B + a + b) + ab. Keep the signs, multiply the base part, then finish the addition or subtraction with any carry or borrowing.

About this lesson

Try the method in a practice when you are ready.

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Give each difference its sign

Choose a nearby base B. Write the numbers as B + a and B + b. A difference above the base is positive; a difference below it is negative. Expanding the product gives (B + a)(B + b) = B(B + a + b) + ab.

For 103 × 107, use B = 100, a = +3 and b = +7. Add the differences to the base: 100 + 3 + 7 = 110. Multiply by the base: 110 × 100 = 11000. Add the correction 3 × 7 = 21 to get 11021.

103 × 107a = +3 b = +7110 × 100= 1100011000 + 21= 11021
Positive differences give a positive correction.

Carry or borrow in the final step

For 113 × 117, the differences are +13 and +17. The base part is (100 + 13 + 17) × 100 = 13000. The correction is 13 × 17 = 221. Adding it gives 13221: 221 adds two hundreds and 21 more. Do the final addition; writing two blocks of digits side by side can fail.

For 97 × 104, the differences are −3 and +4. The base part is (100 − 3 + 4) × 100 = 10100. The correction is (−3) × 4 = −12. Subtract 12: 10100 − 12 = 10088. Borrow one hundred: 10100 = 10000 + 100, and 100 − 12 = 88.

The same rule works at 1000. For 998 × 1003, use −2 and +3: (1000 − 2 + 3) × 1000 = 1001000. The correction is −6, so the answer is 1000994. Borrow from the base part: 1001000 = 1000000 + 1000, and 1000 − 6 = 994.

113 × 117a = +13 b = +17130 × 100= 1300013000 + 221= 13221
221 carries into the hundreds.
97 × 104a = −3 b = +4101 × 100= 1010010100 − 12= 10088
A negative correction reduces the total.
998 × 1003a = −2 b = +31001 × 1000= 10010001001000 − 6= 1000994
At base 1000, borrow a thousand.

Keep the correction negative

Try 96 × 108 around 100. The differences are −4 and +8. The base part is (100 − 4 + 8) × 100 = 10400. Decide the sign of (−4) × 8 before finishing.

The next practice opens Extended, Level 2, Ten questions for two numbers above 100. Level 3 puts the numbers on opposite sides of 100. Level 4 uses opposite sides of 1000, with larger gaps than the small teaching example above.

96 × 108a = −4 b = +8104 × 100= 10400(−4) × (+8) = ?
Find the sign before the final adjustment.

Try it

What is 96 × 108 after applying the signed correction to 10400?

  1. 10432
  2. 10368
Show the answer

10368

Yes. The correction is (−4) × 8 = −32. So 10400 − 32 = 10368. Check by splitting: 96 × 100 + 96 × 8 = 9600 + 768 = 10368.

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